3.204 \(\int \frac{(d+e x)^{3/2} \log (a+b x)}{a+b x} \, dx\)

Optimal. Leaf size=381 \[ -\frac{2 (b d-a e)^{3/2} \text{PolyLog}\left (2,1-\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}-\frac{16 \sqrt{d+e x} (b d-a e)}{3 b^2}+\frac{2 \sqrt{d+e x} (b d-a e) \log (a+b x)}{b^2}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}-\frac{2 (b d-a e)^{3/2} \log (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2}}-\frac{4 (b d-a e)^{3/2} \log \left (\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2}}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{4 (d+e x)^{3/2}}{9 b} \]

[Out]

(-16*(b*d - a*e)*Sqrt[d + e*x])/(3*b^2) - (4*(d + e*x)^(3/2))/(9*b) + (16*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*S
qrt[d + e*x])/Sqrt[b*d - a*e]])/(3*b^(5/2)) + (2*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d -
a*e]]^2)/b^(5/2) + (2*(b*d - a*e)*Sqrt[d + e*x]*Log[a + b*x])/b^2 + (2*(d + e*x)^(3/2)*Log[a + b*x])/(3*b) - (
2*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]]*Log[a + b*x])/b^(5/2) - (4*(b*d - a*e)^(3
/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]]*Log[2/(1 - (Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e])])/b^(
5/2) - (2*(b*d - a*e)^(3/2)*PolyLog[2, 1 - 2/(1 - (Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e])])/b^(5/2)

________________________________________________________________________________________

Rubi [A]  time = 1.5299, antiderivative size = 381, normalized size of antiderivative = 1., number of steps used = 20, number of rules used = 14, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.609, Rules used = {2411, 2346, 63, 208, 2348, 12, 1587, 6741, 5984, 5918, 2402, 2315, 2319, 50} \[ -\frac{2 (b d-a e)^{3/2} \text{PolyLog}\left (2,1-\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}-\frac{16 \sqrt{d+e x} (b d-a e)}{3 b^2}+\frac{2 \sqrt{d+e x} (b d-a e) \log (a+b x)}{b^2}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}-\frac{2 (b d-a e)^{3/2} \log (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2}}-\frac{4 (b d-a e)^{3/2} \log \left (\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2}}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{4 (d+e x)^{3/2}}{9 b} \]

Antiderivative was successfully verified.

[In]

Int[((d + e*x)^(3/2)*Log[a + b*x])/(a + b*x),x]

[Out]

(-16*(b*d - a*e)*Sqrt[d + e*x])/(3*b^2) - (4*(d + e*x)^(3/2))/(9*b) + (16*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*S
qrt[d + e*x])/Sqrt[b*d - a*e]])/(3*b^(5/2)) + (2*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d -
a*e]]^2)/b^(5/2) + (2*(b*d - a*e)*Sqrt[d + e*x]*Log[a + b*x])/b^2 + (2*(d + e*x)^(3/2)*Log[a + b*x])/(3*b) - (
2*(b*d - a*e)^(3/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]]*Log[a + b*x])/b^(5/2) - (4*(b*d - a*e)^(3
/2)*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]]*Log[2/(1 - (Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e])])/b^(
5/2) - (2*(b*d - a*e)^(3/2)*PolyLog[2, 1 - 2/(1 - (Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e])])/b^(5/2)

Rule 2411

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + (g_.)*(x_))^(q_.)*((h_.) + (i_.)*(x_))
^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((g*x)/e)^q*((e*h - d*i)/e + (i*x)/e)^r*(a + b*Log[c*x^n])^p, x], x,
d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, n, p, q, r}, x] && EqQ[e*f - d*g, 0] && (IGtQ[p, 0] || IGtQ[
r, 0]) && IntegerQ[2*r]

Rule 2346

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.))/(x_), x_Symbol] :> Dist[d, Int[((d
+ e*x)^(q - 1)*(a + b*Log[c*x^n])^p)/x, x], x] + Dist[e, Int[(d + e*x)^(q - 1)*(a + b*Log[c*x^n])^p, x], x] /
; FreeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && GtQ[q, 0] && IntegerQ[2*q]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 2348

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_.))/(x_), x_Symbol] :> With[{u = IntHi
de[(d + e*x^r)^q/x, x]}, Simp[u*(a + b*Log[c*x^n]), x] - Dist[b*n, Int[Dist[1/x, u, x], x], x]] /; FreeQ[{a, b
, c, d, e, n, r}, x] && IntegerQ[q - 1/2]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 1587

Int[(Pp_)/(Qq_), x_Symbol] :> With[{p = Expon[Pp, x], q = Expon[Qq, x]}, Simp[(Coeff[Pp, x, p]*Log[RemoveConte
nt[Qq, x]])/(q*Coeff[Qq, x, q]), x] /; EqQ[p, q - 1] && EqQ[Pp, Simplify[(Coeff[Pp, x, p]*D[Qq, x])/(q*Coeff[Q
q, x, q])]]] /; PolyQ[Pp, x] && PolyQ[Qq, x]

Rule 6741

Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =!= u]

Rule 5984

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Simp[(a + b*ArcTanh[c
*x])^(p + 1)/(b*e*(p + 1)), x] + Dist[1/(c*d), Int[(a + b*ArcTanh[c*x])^p/(1 - c*x), x], x] /; FreeQ[{a, b, c,
d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0]

Rule 5918

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[((a + b*ArcTanh[c*x])^p*
Log[2/(1 + (e*x)/d)])/e, x] + Dist[(b*c*p)/e, Int[((a + b*ArcTanh[c*x])^(p - 1)*Log[2/(1 + (e*x)/d)])/(1 - c^2
*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d^2 - e^2, 0]

Rule 2402

Int[Log[(c_.)/((d_) + (e_.)*(x_))]/((f_) + (g_.)*(x_)^2), x_Symbol] :> -Dist[e/g, Subst[Int[Log[2*d*x]/(1 - 2*
d*x), x], x, 1/(d + e*x)], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[c, 2*d] && EqQ[e^2*f + d^2*g, 0]

Rule 2315

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[PolyLog[2, 1 - c*x]/e, x] /; FreeQ[{c, d, e}, x] &
& EqQ[e + c*d, 0]

Rule 2319

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.), x_Symbol] :> Simp[((d + e*x)^(q + 1
)*(a + b*Log[c*x^n])^p)/(e*(q + 1)), x] - Dist[(b*n*p)/(e*(q + 1)), Int[((d + e*x)^(q + 1)*(a + b*Log[c*x^n])^
(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && GtQ[p, 0] && NeQ[q, -1] && (EqQ[p, 1] || (Integers
Q[2*p, 2*q] &&  !IGtQ[q, 0]) || (EqQ[p, 2] && NeQ[q, 1]))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rubi steps

\begin{align*} \int \frac{(d+e x)^{3/2} \log (a+b x)}{a+b x} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{b d-a e}{b}+\frac{e x}{b}\right )^{3/2} \log (x)}{x} \, dx,x,a+b x\right )}{b}\\ &=\frac{e \operatorname{Subst}\left (\int \sqrt{\frac{b d-a e}{b}+\frac{e x}{b}} \log (x) \, dx,x,a+b x\right )}{b^2}+\frac{(b d-a e) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{b d-a e}{b}+\frac{e x}{b}} \log (x)}{x} \, dx,x,a+b x\right )}{b^2}\\ &=\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 \operatorname{Subst}\left (\int \frac{\left (\frac{b d-a e}{b}+\frac{e x}{b}\right )^{3/2}}{x} \, dx,x,a+b x\right )}{3 b}+\frac{(e (b d-a e)) \operatorname{Subst}\left (\int \frac{\log (x)}{\sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}} \, dx,x,a+b x\right )}{b^3}+\frac{(b d-a e)^2 \operatorname{Subst}\left (\int \frac{\log (x)}{x \sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}} \, dx,x,a+b x\right )}{b^3}\\ &=-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}-\frac{(2 (b d-a e)) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}}{x} \, dx,x,a+b x\right )}{3 b^2}-\frac{(2 (b d-a e)) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}}{x} \, dx,x,a+b x\right )}{b^2}-\frac{(b d-a e)^2 \operatorname{Subst}\left (\int -\frac{2 \sqrt{b} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d-\frac{a e}{b}+\frac{e x}{b}}}{\sqrt{b d-a e}}\right )}{\sqrt{b d-a e} x} \, dx,x,a+b x\right )}{b^3}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}+\frac{\left (2 (b d-a e)^{3/2}\right ) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d-\frac{a e}{b}+\frac{e x}{b}}}{\sqrt{b d-a e}}\right )}{x} \, dx,x,a+b x\right )}{b^{5/2}}-\frac{\left (2 (b d-a e)^2\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}} \, dx,x,a+b x\right )}{3 b^3}-\frac{\left (2 (b d-a e)^2\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{\frac{b d-a e}{b}+\frac{e x}{b}}} \, dx,x,a+b x\right )}{b^3}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}+\frac{\left (4 (b d-a e)^{3/2}\right ) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b d-a e}}\right )}{a e+b \left (-d+x^2\right )} \, dx,x,\sqrt{d+e x}\right )}{b^{3/2}}-\frac{\left (4 (b d-a e)^2\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{b d-a e}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{3 b^2 e}-\frac{\left (4 (b d-a e)^2\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{b d-a e}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{b^2 e}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}+\frac{\left (4 (b d-a e)^{3/2}\right ) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b d-a e}}\right )}{-b d+a e+b x^2} \, dx,x,\sqrt{d+e x}\right )}{b^{3/2}}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}-\frac{(4 (b d-a e)) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b d-a e}}\right )}{1-\frac{\sqrt{b} x}{\sqrt{b d-a e}}} \, dx,x,\sqrt{d+e x}\right )}{b^2}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}-\frac{4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}+\frac{(4 (b d-a e)) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-\frac{\sqrt{b} x}{\sqrt{b d-a e}}}\right )}{1-\frac{b x^2}{b d-a e}} \, dx,x,\sqrt{d+e x}\right )}{b^2}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}-\frac{4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}-\frac{\left (4 (b d-a e)^{3/2}\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}\\ &=-\frac{16 (b d-a e) \sqrt{d+e x}}{3 b^2}-\frac{4 (d+e x)^{3/2}}{9 b}+\frac{16 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{3 b^{5/2}}+\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )^2}{b^{5/2}}+\frac{2 (b d-a e) \sqrt{d+e x} \log (a+b x)}{b^2}+\frac{2 (d+e x)^{3/2} \log (a+b x)}{3 b}-\frac{2 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log (a+b x)}{b^{5/2}}-\frac{4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}-\frac{2 (b d-a e)^{3/2} \text{Li}_2\left (1-\frac{2}{1-\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}}\right )}{b^{5/2}}\\ \end{align*}

Mathematica [A]  time = 1.02853, size = 663, normalized size = 1.74 \[ \frac{-18 (b d-a e)^{3/2} \text{PolyLog}\left (2,\frac{1}{2}-\frac{\sqrt{b} \sqrt{d+e x}}{2 \sqrt{b d-a e}}\right )+18 (b d-a e)^{3/2} \text{PolyLog}\left (2,\frac{1}{2} \left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}+1\right )\right )+12 b^{3/2} (d+e x)^{3/2} \log (a+b x)+36 b^{3/2} d \sqrt{d+e x} \log (a+b x)+96 a \sqrt{b} e \sqrt{d+e x}-9 (b d-a e)^{3/2} \log ^2\left (\sqrt{b d-a e}-\sqrt{b} \sqrt{d+e x}\right )+9 (b d-a e)^{3/2} \log ^2\left (\sqrt{b d-a e}+\sqrt{b} \sqrt{d+e x}\right )+18 (b d-a e)^{3/2} \log (a+b x) \log \left (\sqrt{b d-a e}-\sqrt{b} \sqrt{d+e x}\right )-18 (b d-a e)^{3/2} \log \left (\frac{1}{2} \left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}+1\right )\right ) \log \left (\sqrt{b d-a e}-\sqrt{b} \sqrt{d+e x}\right )-36 a \sqrt{b} e \sqrt{d+e x} \log (a+b x)-18 (b d-a e)^{3/2} \log (a+b x) \log \left (\sqrt{b d-a e}+\sqrt{b} \sqrt{d+e x}\right )+18 (b d-a e)^{3/2} \log \left (\sqrt{b d-a e}+\sqrt{b} \sqrt{d+e x}\right ) \log \left (\frac{1}{2}-\frac{\sqrt{b} \sqrt{d+e x}}{2 \sqrt{b d-a e}}\right )+96 b d \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )-96 a e \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )-8 b^{3/2} (d+e x)^{3/2}-96 b^{3/2} d \sqrt{d+e x}}{18 b^{5/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x)^(3/2)*Log[a + b*x])/(a + b*x),x]

[Out]

(-96*b^(3/2)*d*Sqrt[d + e*x] + 96*a*Sqrt[b]*e*Sqrt[d + e*x] - 8*b^(3/2)*(d + e*x)^(3/2) + 96*b*d*Sqrt[b*d - a*
e]*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]] - 96*a*e*Sqrt[b*d - a*e]*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/S
qrt[b*d - a*e]] + 36*b^(3/2)*d*Sqrt[d + e*x]*Log[a + b*x] - 36*a*Sqrt[b]*e*Sqrt[d + e*x]*Log[a + b*x] + 12*b^(
3/2)*(d + e*x)^(3/2)*Log[a + b*x] + 18*(b*d - a*e)^(3/2)*Log[a + b*x]*Log[Sqrt[b*d - a*e] - Sqrt[b]*Sqrt[d + e
*x]] - 9*(b*d - a*e)^(3/2)*Log[Sqrt[b*d - a*e] - Sqrt[b]*Sqrt[d + e*x]]^2 - 18*(b*d - a*e)^(3/2)*Log[a + b*x]*
Log[Sqrt[b*d - a*e] + Sqrt[b]*Sqrt[d + e*x]] + 9*(b*d - a*e)^(3/2)*Log[Sqrt[b*d - a*e] + Sqrt[b]*Sqrt[d + e*x]
]^2 + 18*(b*d - a*e)^(3/2)*Log[Sqrt[b*d - a*e] + Sqrt[b]*Sqrt[d + e*x]]*Log[1/2 - (Sqrt[b]*Sqrt[d + e*x])/(2*S
qrt[b*d - a*e])] - 18*(b*d - a*e)^(3/2)*Log[Sqrt[b*d - a*e] - Sqrt[b]*Sqrt[d + e*x]]*Log[(1 + (Sqrt[b]*Sqrt[d
+ e*x])/Sqrt[b*d - a*e])/2] - 18*(b*d - a*e)^(3/2)*PolyLog[2, 1/2 - (Sqrt[b]*Sqrt[d + e*x])/(2*Sqrt[b*d - a*e]
)] + 18*(b*d - a*e)^(3/2)*PolyLog[2, (1 + (Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e])/2])/(18*b^(5/2))

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Maple [F]  time = 180., size = 0, normalized size = 0. \begin{align*} \int{\frac{\ln \left ( bx+a \right ) }{bx+a} \left ( ex+d \right ) ^{{\frac{3}{2}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^(3/2)*ln(b*x+a)/(b*x+a),x)

[Out]

int((e*x+d)^(3/2)*ln(b*x+a)/(b*x+a),x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*log(b*x+a)/(b*x+a),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (e x + d\right )}^{\frac{3}{2}} \log \left (b x + a\right )}{b x + a}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*log(b*x+a)/(b*x+a),x, algorithm="fricas")

[Out]

integral((e*x + d)^(3/2)*log(b*x + a)/(b*x + a), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**(3/2)*ln(b*x+a)/(b*x+a),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{\frac{3}{2}} \log \left (b x + a\right )}{b x + a}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*log(b*x+a)/(b*x+a),x, algorithm="giac")

[Out]

integrate((e*x + d)^(3/2)*log(b*x + a)/(b*x + a), x)